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Question

Factorise the polynomial x2+33x+6 by splitting the middle term

A
(x+3)(x23)
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B
(x3)(x+23)
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C
(x+3)(x+23)
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D
(x3)(x23)
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Solution

The correct option is C (x+3)(x+23)
We have, x2+33x+6=x2+(3+23)x+6 ( 3+23=33 and (3)(23)=6 )
=x2+3x+23x+(3)(23)
={x2+3x}+{23x+(3)(23)}
=x(x+3)+23(x+3)
=(x+3)(x+23)
x2+33x+6=(x+3)(x+23)

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