Factorise the term a2+bc+ab+ac
(a+b2)(a+c).
(a+b)(a+c).
(a2+b)(a+c).
(a+b)(a−c).
The expression is a2+bc+ab+ac By suitably rearranging the terms, we have; =a2+ab+ac+bc =a(a+b)+c(a+b) =(a+b)(a+c).
Factorise: a8−2a4b4+b8
a2+bc+ab+ac=?(a) (a+b)(a+c)(b) (a+b)(b+c)(c) (b+c)(c+a)(d) a(a+b+c)