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Question
Factorise - (x-1)3+(x-2)3+(3-2x)3
Factorise - (x-1)3+(x-2)3+(3-2x)3
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Solution
(x−1)³+(x−2)³+(3−2x)³
=(x-1)(x-1)² + (x-2)(x-2)² + (3-2x)(3-2x)²
=−6x³+27x²−39x+18
=3(−x+1)(x−2)(2x−3)
=(x-1)(x-1)² + (x-2)(x-2)² + (3-2x)(3-2x)²
=−6x³+27x²−39x+18
=3(−x+1)(x−2)(2x−3)
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