X^2 17x+16=x^2 x 16x+16 ∵ 16=( 1)× ( 16) amp; 17= 1 16 amp; =x(x 1) 16(x 1) =(x 1)(x 16) 𝐀𝐧𝐬. ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Factorisation by Regrouping Terms

Factorise: x2...

Question

Factorise:
$x^{2} - 17 x + 16$

Open in App

Solution

$x^{2} - 17 x + 16 = x^{2} - x - 16 x + 16 {\begin{matrix} ∵ 16 = (- 1) \times (- 16) 17 = - 1 - 16 \end{matrix}} = x (x - 1) - 16 (x - 1) = (x - 1) (x - 16) A n s .$

Suggest Corrections

Similar questions

Factorise:
$x^{2} + 8 x + 16$

Factorise:
$x^{2} - 2 x + \frac{7}{16}$

y = e^{{({sin}^{2} x + {sin}^{4} x + {sin}^{6} x + \dots) {log}_{e} 2}}

x^{2} - 17 x + 16 = 0,

0 < x < \frac{π}{2} .

List I

List II .

\begin{matrix} List I & List II (a) & \frac{2 sin 2 x}{1 + {cos}^{2} x} & (p) & 1 (b) & \frac{2 sin x}{sin x + cos x} & (q) & \frac{4}{9} (c) & \infty \sum n = 1 (cot x)^{n} & (r) & \frac{2}{3} (d) & \infty \sum n = 1 n (cot x)^{2 n} & (s) & \frac{4}{3} \end{matrix}

The sum of the coefficients of the polynomial p(x)=(3x-2^17(x+1)^4 is:

-1

Please explain.

Join BYJU'S Learning Program