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Question

Factorise :
x2−(2y+3z)2

A
(xy+3x)(7x2y3z)
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B
(x+y+3x)(x2yz)
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C
(x2y+3x)(7xy3z)
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D
(x+2y+3x)(x2y3z)
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Solution

The correct option is D (x+2y+3x)(x2y3z)
x2(2y+3z)2
Using,
(a2b2)=(a+b)(ab)
=(x+2y+3z)(x2y3z)

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