Question

Factorise : $x^2+3\sqrt{3}x+6$

Answer 1

$x^2+3\sqrt{3}x+6$

This can be written as

$\Rightarrow x^2+\sqrt{3}x+2\sqrt{3}x+6$

$\Rightarrow x(x+\sqrt{3})+2\sqrt{3}(x+\sqrt{3})$

$\Rightarrow (x+\sqrt{3})(x+2\sqrt{3})$

Therefore, $\Rightarrow x^2+3\sqrt{3}x+6=(x+\sqrt{3})(x+2\sqrt{3})$