Question

Factorise: $x^2-3bx-ax+3ab$.

Answer 1

$x^2-3bx-ax+3ab$

$=x(x-3b)-a(x-3b)$

$=(x-a)(x-3b)$

$\therefore x^2-3bx-ax+3ab=(x-a)(x-3b)$

Hence factorized.