Factorise- x2-5-3x-12

The correct option is B (x+√(3))(x+4√(3)) x^2+5√(3)x+12 =x^2+4√(3)x+√(3)x+12 =x(x+4√(3))+√(3)(x+4√(3)) =(x+4√(3))(x+√(3)) ...

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Byju's Answer

Standard X

Mathematics

Solving a Quadratic Equation by Factorization Method

Factorise: ...

Question

Factorise: $x^{2} + 5 \sqrt{3} x + 12$

(x + 2 \sqrt{3}) (x + 3 \sqrt{3})

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(x + \sqrt{3}) (x + 4 \sqrt{3})

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(x + 4 \sqrt{3}) (x - \sqrt{3})

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(x - \sqrt{3}) (x - 4 \sqrt{3})

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Solution

The correct option is B $(x + \sqrt{3}) (x + 4 \sqrt{3})$
$x^{2} + 5 \sqrt{3} x + 12$
$= x^{2} + 4 \sqrt{3} x + \sqrt{3} x + 12$
$= x (x + 4 \sqrt{3}) + \sqrt{3} (x + 4 \sqrt{3})$
$= (x + 4 \sqrt{3}) (x + \sqrt{3})$

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Similar questions

(3 x - 3 x^{2} - 12 + x^{4} + x^{3}) \div (2 + x^{2})

Solve :

$(i) \frac{1}{3} x - 6 = \frac{5}{2} (i i) \frac{2 x}{3} - \frac{3 x}{8} = \frac{7}{12} (i i i) (x + 2) (x + 3) + (x - 3) (x - 2) - 2 x (x + 1) = 0 (i v) \frac{1}{10} - \frac{7}{x} = 35 (v) 13 (x - 4) - 3 (x - 9) - 4 (x + 4) = 0 (v i) x + 7 - \frac{8 x}{3} = \frac{17 x}{6} - \frac{5 x}{8} (v i i) \frac{3 x - 2}{4} - \frac{2 x + 3}{3} = \frac{2}{3} - x (v i i i) \frac{x + 2}{6} - (\frac{11 - x}{3} - \frac{1}{4}) = \frac{3 x - 4}{12} (i x) \frac{2}{5 x} - \frac{5}{3 x} = \frac{1}{15} (x) \frac{x + 2}{3} - \frac{x + 1}{5} = \frac{x - 3}{4} - 1 (x i) \frac{3 x - 2}{3} + \frac{2 x + 3}{2} = x + \frac{7}{6} (x i i) x - \frac{x - 1}{2} = 1 - \frac{x - 2}{3} (x i i i) \frac{9 x + 7}{2} - (x - \frac{x - 2}{7}) = 36 (x i v) \frac{6 x + 1}{2} + 1 = \frac{7 x - 3}{3}$

Q. Factorise:

3 x^{5} y - 27 x^{4} y^{2} + 12 x^{3} y^{3}

Q. Factorize:

(i)

x^{3} + 3 x^{2} + 3 x - 7

(ii)

x^{3} - 3 x^{2} + 3 x + 7

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Q. Factorise

3 x^{5} - 6 x^{4} - 2 x^{3} + 4 x^{2} + x - 2

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Factorise: x2+5√3x+12

The correct option is B (x+√3)(x+4√3)x2+5√3x+12=x2+4√3x+√3x+12=x(x+4√3)+√3(x+4√3)=(x+4√3)(x+√3)

Factorise: $x^{2} + 5 \sqrt{3} x + 12$

The correct option is B $(x + \sqrt{3}) (x + 4 \sqrt{3})$
$x^{2} + 5 \sqrt{3} x + 12$
$= x^{2} + 4 \sqrt{3} x + \sqrt{3} x + 12$
$= x (x + 4 \sqrt{3}) + \sqrt{3} (x + 4 \sqrt{3})$
$= (x + 4 \sqrt{3}) (x + \sqrt{3})$