The correct option is B (x 1)(x 5) x^2 6x+5 #160; =x^2 1x 5x+5 #160;(Rewrite 6x as x 5x to make grouping and factoring easie ...

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Factorisation Using Algebraic Identities

Factorise: ...

Question

Factorise: $x^{2} - 6 x + 5$

(x + 1) (x + 5)

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(x - 1) (x - 5)

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(x - 1) (x + 5)

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(x + 1) (x - 5)

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Solution

The correct option is B $(x - 1) (x - 5)$
$x^{2} - 6 x + 5$
$= x^{2} - 1 x - 5 x + 5$ (Rewrite $- 6 x$ as $- x - 5 x$ to make grouping and factoring easier.)
$= x (x - 1) - 5 (x - 1)$
$= (x - 1) (x - 5)$
Therefore $x^{2} - 6 x + 5 = (x - 1) (x - 5)$

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