Factorise : $x^{2} + 6 x + 8$

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Solution

Given that: $x^{2} + 6 x + 8$
$= x^{2} + 4 x + 2 x + 8$ , (split middle term)
$= (x^{2} + 4 x) + (2 x + 8)$ , (group pair of terms)
$= x (x + 4) + 2 (x + 4)$ , (factor each binomials)
$= (x + 4) (x + 2)$ , (factor out common factor $(x + 4)$
Hence factors of $x^{2} + 6 x + 8$ are $(x + 4) (x + 2)$

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