Factorise $x^{2} - 6 x + 9$

(x + 3)(x - 3)

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(x - 3)(x - 3)

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(x + 3)(x + 3)

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(x + 3)(x - 2)

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Solution

The correct option is B (x - 3)(x - 3)
The given expression is of the form:
$x^{2} - 2 x y + y^{2}$ = $(x - y)^{2}$
So in $x^{2} - 6 x + 9$ ,
$x^{2} = x^{2}$ and $y^{2} = 9$ . Hence x =x and y = $\sqrt{9}$ = 3
i,e, $x^{2} - 6 x + 9$ = $(x - 3)^{2}$
$∴$ factors are (x-3)(x-3)

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