Factorise:
$x^{2} + 8 x + 16$

(x - 4)^{2}

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(x - 2)^{2}

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(x + 4)^{2}

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(x + 2)^{2}

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Solution

The correct option is C $(x + 4)^{2}$
$x^{2} + 8 x + 16$
$= x^{2} + 2 \times 4 \times x + 4^{2}$ , Using $a^{2} + b^{2} + 2 a b = (a + b)^{2}$
$= (x + 4)^{2}$

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