Question

Factorise $x^2-\frac{13}{24}x-\frac{1}{12}$

• A. $\frac{1}{24}(3x-2)(8x+1)$
• B. $\frac{1}{8}(3x-2)(8x+1)$
• C. $\frac{1}{4}(3x-2)(8x+1)$
• D. $\frac{1}{26}(3x-2)(8x+1)$

Answer 1

The correct option is A $\frac{1}{24}(3x-2)(8x+1)$

$x^2-\frac{13x}{24}-\frac{1}{12}$

$\Rightarrow \frac{1}{24}(24x^2-13x-2)$

$\Rightarrow \frac{1}{24}(24x^2-16x+3x-2)$

$\Rightarrow \frac{1}{24}\left(8x\right(3x-2)+1(3x-2\left)\right)$

$\Rightarrow \frac{1}{24}(8x+1)(3x-2)$.