CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Factorise:

x2y24xz+4z2

Open in App
Solution

x2y24xz+4z2=x24xz+4z2y2=(x)22×x2z+(2z)2(y)2=(x2z)2(y)2=(x2z+y)(x2zy)=(x+y2z)(xy2z)


flag
Suggest Corrections
thumbs-up
49
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Question 1-5
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon