Question

Factorise $x^2{y}^2-p^2{q}^2$.

Answer 1

Step:-1 As we know the algebraic identity,

$a^2-b^2=(a+b)(a-b)$

So, it can be factorized by using this identity, we can write:

$x^2{y}^2-p^2{q}^2$ = ${\left(xy\right)}^2-{\left(pq\right)}^2$

= $(xy+pq)(xy-pq)$

Therefore factors of $x^2{y}^2-p^2{q}^2$ =$(xy+pq)(xy-pq)$.