Factorise :
$(x - 2 y)^{2} - 4 x + 8 y$

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Solution

We have,
$(x - 2 y)^{2} - 4 x + 8 y$
$= (x - 2 y)^{2} - 4 (x - 2 y) [T a k i n g - 4 c o m m o n f r o m - 4 x + 8 y]$
$= (x - 2 y) {\begin{matrix} (x - 2 y) - 4) \end{matrix}} [T a k i n g (x - 2 y) c o m m o n]$
$= (x - 2 y) (x - 2 y - 4)$

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