Factorise :
$(x - 2 y)^{2} - 4 x + 8 y$

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Solution

We have,
$(x - 2 y)^{2} - 4 x + 8 y$
$= (x - 2 y)^{2} - 4 (x - 2 y) [Taking -4 common from - 4 x + 8 y]$
$= (x - 2 y) (x - 2 y - 4) [Taking (x - 2 y) common]$
$= (x - 2 y) (x - 2 y - 4)$

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(x - 2 y)^{2} - 4 x + 8 y

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