Question

Factorise: $x^2{y}^2-64$

Answer 1

We need to factorise $x^2{y}^2-64$

It can be written as

$(x^2{y}^2-64)$

$=\left[\right(xy{)}^2-8^2]$

$=(xy-8)(xy+8)$

Thus the factors are $(xy-8)$ and $(xy+8)$.