x3 + 13x2 + 32x + 20
Let p(x) = x3 + 13x2 + 32x + 20
Put x = –1 in p(x), we get
p(–1) = (–1)3 + 13(–1)2 + 32(–1) + 20
= (–1) + 13 + (–32) + 20
= 33 – 33 = 0
Hence (x + 1) is a factor of p(x)
Now divide p(x) with (x + 1), we get x2 + 12x + 20
∴ p(x) = (x + 1)(x2 + 12x + 20)
Let's factorize x2 + 12x + 20
⇒ p(x) = (x + 1)(x2 + 10x + 2x + 20)
= (x + 1)[x(x + 10) + 2(x + 10)]
= (x + 1)(x + 10)(x + 2)