The correct option is B (x 2)(x^2 + 2x + 4) x^3 8 = x^3 2^3 = (x 2)(x^2 +2x+ 4) #160; ...

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Standard IX

Mathematics

Division of a Polynomial by a Monomial

Factorise: ...

Question

Factorise: $x^{3} - 8$ .

(x + 2) (x^{2} + 2 x + 4)

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(x - 2) (x^{2} + 2 x + 4)

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(x - 2) (x^{2} - 2 x + 4)

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(x - 2) (x^{2} + 2 x - 4)

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Solution

The correct option is B $(x - 2) (x^{2} + 2 x + 4)$
$x^{3} - 8 = x^{3} - 2^{3} = (x - 2) (x^{2} + 2 x + 4)$

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Find the discriminant of each of the following equations :
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{lim}_{x \to \sqrt{2}} \frac{x^{2} - 2}{x^{2} + \sqrt{2 x} - 4}

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Factorise: x3−8.

The correct option is B (x−2)(x2+2x+4)x3−8=x3−23=(x−2)(x2+2x+4)

Factorise: $x^{3} - 8$ .

The correct option is B $(x - 2) (x^{2} + 2 x + 4)$
$x^{3} - 8 = x^{3} - 2^{3} = (x - 2) (x^{2} + 2 x + 4)$