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Question

Factorise :
x3−8y3−64z3−24xyz

A
(x2y4z)(x2+4y2+16z2+xy8yz+4xz)
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B
(x2y4z)(x2+4y2+16z2+2xy8yz+4xz)
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C
(4z)(x2+4y2+16z2+2xy8yz+4xz)
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D
(2y4z)(x2+4y2+16z2+2xy8yz+4xz)
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Solution

The correct option is B (x2y4z)(x2+4y2+16z2+2xy8yz+4xz)
x38y364z324xyz
a3+b3+c33abc=(a+b+c)(a2+b2+c2abbcca)
Comparing with the expression of standard formulae,
Here,
a=x
b=2y
c=4z
Therefore,
=>x3+(2y)3+(4z)33(x)(2y)(4z)=(x2y4z)(x2+4y2+16z2+2xy8yz+4xz)

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