The correct option is B (x−2y−4z)(x2+4y2+16z2+2xy−8yz+4xz)
x3−8y3−64z3−24xyz
a3+b3+c3−3abc=(a+b+c)(a2+b2+c2−ab−bc−ca)
Comparing with the expression of standard formulae,
Here,
a=x
b=−2y
c=−4z
Therefore,
=>x3+(−2y)3+(−4z)3−3(x)(−2y)(−4z)=(x−2y−4z)(x2+4y2+16z2+2xy−8yz+4xz)