Factorise: $x^{3} y^{2} - z x^{2} y + x^{4} y^{3}$

$x^{2} (x y - z + x^{2} y^{2})$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$x y^{2} (x y - z + x^{2} y^{2})$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$x^{2} y (x y - z + x^{2} y^{2})$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$x y (x y - z + x^{2} y^{2})$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
$x^{2} y (x y - z + x^{2} y^{2})$

$x^{3} y^{2} - z x^{2} y + x^{4} y^{3}$
$= (x \times x \times x \times y \times y) - (z \times x \times x \times y) + (x \times x \times x \times x \times y \times y^{2})$
$= x^{2} y (x y - z + x^{2} y^{2})$

Suggest Corrections

Similar questions

x^{3} y^{2} - z x^{2} y + x^{4} y^{3} =

\times (x y - z + x^{2} y^{2})

x^{3} y^{2} - z x^{2} y + x^{4} y^{3} =

\times (x y - z + x^{2} y^{2})

\sqrt{x^{3} y^{3}} \div \sqrt[3]{x^{4} y^{3}}

y = x e^{\frac{1}{x}}

x^{3} y_{2} + x y_{1} =

(a + b x) e^{y / x} = x

x^{3} y_{2} =

Join BYJU'S Learning Program