1
Question
Factorise:
(x-3y)3+(3y-7z)3+(7z-x)3
Factorise:
(x-3y)3+(3y-7z)3+(7z-x)3
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Solution
We have to factorize,
(x − 3y)3 + (3y − 7z)3 + (7z − x)3
.Let a = x − 3y ; b = 3y − 7z ; c = 7z − x
now, a + b + c = (x − 3y) + (3y − 7z) + (7z − x) = 0
Since, a + b + c = 0, then we have
(x − 3y)3 + (3y − 7z)3 + (7z − x)3
.Let a = x − 3y ; b = 3y − 7z ; c = 7z − x
now, a + b + c = (x − 3y) + (3y − 7z) + (7z − x) = 0
Since, a + b + c = 0, then we have
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