Factorise $x^{4} - 5 x^{2} + 6$ .

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Solution

Now,
$x^{4} - 5 x^{2} + 6$
$= x^{4} - 3 x^{2} - 2 x^{2} + 6$
$= x^{2} (x^{2} - 3) - 2 (x^{2} - 3)$
$= (x^{2} - 2) (x^{2} - 3)$ .

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Factorise x4−5x2+6.

Now,x4−5x2+6=x4−3x2−2x2+6=x2(x2−3)−2(x2−3)=(x2−2)(x2−3).

Factorise $x^{4} - 5 x^{2} + 6$ .

Now,
$x^{4} - 5 x^{2} + 6$
$= x^{4} - 3 x^{2} - 2 x^{2} + 6$
$= x^{2} (x^{2} - 3) - 2 (x^{2} - 3)$
$= (x^{2} - 2) (x^{2} - 3)$ .