Factorise: $x^{4} + y^{4} - 3 x^{2} y^{2}$

(x^{2} - y^{2} - x y) (x^{2} - y^{2} + x^{2} y)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(x^{2} - y^{2} + x y) (x^{2} - y^{2} + x)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(x^{2} - y^{2} - x y) (x^{2} + y^{2} + y)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(x^{2} - y^{2} - x y) (x^{2} - y^{2} + x y)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is C $(x^{2} - y^{2} - x y) (x^{2} - y^{2} + x y)$
$x^{4} + y^{4} - 3 x^{2} y^{2}$
$= (x^{2})^{2} + (y^{2})^{2} - 2 x^{2} y^{2} - x^{2} y^{2}$
$= (x^{2} - y^{2})^{2} - (x y)^{2}$
$= (x^{2} - y^{2} + x y) (x^{2} - y^{2} - x y)$

Suggest Corrections

Similar questions

x y (x^{2} - y^{2}) = x^{2} + y^{2}

x^{2} + y^{2}

x y (x^{2} - y^{2}) + y z (y^{2} - z^{2}) + z x (z^{2} - x^{2})

x y (x^{2} - 2 x + y^{2})

x = - 1, y = 1

x^{4} + x^{2} y^{2} + y^{4}

(x^{2} - y^{2}) : (x^{2} + y^{2})

(x^{4} - y^{4}) : (x + y)^{4}

Join BYJU'S Learning Program