Factorise
$x^{4} y^{4} - x y$

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Solution

ANSWER:
Using the identity
$a^{3} - b^{3} = (a - b) (a^{2} + b^{2} + a b)$
$x^{4} y^{4} - x y$
= $x y (x^{3} y^{3} - 1)$
= $x y (x y - 1) (x^{2} y^{2} + 1 + x y)$

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