Question

Factorise : $x-64y^4$

Answer 1

Since we know the identity $a^2-b^2=(a+b)(a-b)$

Using the above identity, the equation $x-64y^4$ can be factorised as follows:

$x-64y^4=(\sqrt{x}{)}^2-(8y^2{)}^2=(\sqrt{x}+8y^2)(\sqrt{x}-8y^2)$

Hence, $x-64y^4=(\sqrt{x}+8y^2)(\sqrt{x}-8y^2)$