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Question

Factorise x(xa)y(ya)

A
(x+y)(x+ya)
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B
(x+y)(xya)
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C
(xy)(x+ya)
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D
(xy)(x+y)
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Solution

The correct option is C (xy)(x+ya)
x(xa)y(ya)
= x2axy2ay
Re-arranging , we get
= x2y2axay
We know a2b2=(a+b)(ab)taking a common
= (x+y)(xy)a(xy)
Taking (xy) common
= (xy)(x+ya)

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