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B
(x+y)(x−y−a)
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C
(x−y)(x+y−a)
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D
(x−y)(x+y)
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Solution
The correct option is C(x−y)(x+y−a) x(x−a)−y(y−a) = x2−ax−y2−ay Re-arranging , we get = x2−y2−ax−ay We knowa2−b2=(a+b)(a−b)takingacommon = (x+y)(x−y)−a(x−y) Taking (x−y) common = (x−y)(x+y−a)