Factorise:
$x (x + y)^{3} - 3 x^{2} y (x + y)$

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Solution

$x (x + y)^{3} - 3 x^{2} y (x + y) = x (x + y) [(x + y)^{2} - 3 x y] = x (x + y) (x^{2} + y^{2} + 2 x y - 3 x y) = x (x + y) (x^{2} + y^{2} - x y)$

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Similar questions

Factorise $x (x - y)^{3} + 3 x^{2} y (x - y)$

x (x + y)^{3} - 3 x^{2} y (x + y)

x {(x - y)}^{3} + 3 x^{2} y (x - y)

Factorise:

$x (x - 2) (x - 4) + 4 x - 8$

y^{3} - \frac{1}{y^{3}}

y - \frac{1}{y} = 9

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