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Question

Factorise: x(y2z2)+y(z2x2)+z(x2y2).

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Solution

x(y2z2)+y(z2x2)+z(x2y2)=xy2xz2+yz2yx2+zx2zy2
Arrange the terms in descending order of power of x.
=x2y+zx2+xy2xz2yz+yz2
=x2(yz)+x(y2z2)yz(yz)
=x2(yz)+x(yz)(y+z)yz(yz)
=(yz)[x2+x(y+z)yz]
(yz)[x2+xy+xzyz]

Arrange the term in bracket in descending order of the power of y.
=(yz)[xyyzx2+xz]
=(yz)[y(x+z)+x(x+z)]
=(xy)(yz)(zx).

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