Factorise:
$x^{2} - \sqrt{3} x - 6$

Open in App

Solution

$x^{2} - \sqrt{3} x - 6 = x^{2} - 2 \sqrt{3} x + \sqrt{3} x - 6 = x (x - 2 \sqrt{3}) + \sqrt{3} (x - 2 \sqrt{3}) = (x - 2 \sqrt{3}) (x + \sqrt{3})$

Suggest Corrections

Similar questions

Factorise:
$x^{2} - \sqrt{3} x - 6$

Factorise:
$x^{2} + 3 \sqrt{3} x + 6$

Factorise:
$x^{2} + 2 \sqrt{3} x - 24$

x^{2} + 3 \sqrt{3} x + 6

Join BYJU'S Learning Program