Factorise
x³ – 3x²+ 3x + 7

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Solution

x³ – 3x²+ 3x + 7
$= x^{3} - 3 x^{2} + 3 x + 7 = x^{3} - 3 x^{2} + 3 x + 8 - 1 = x^{3} - 3 x^{2} + 3 x - 1 + 8 = (x^{3} - 3 x^{2} + 3 x - 1) + 8 = {(x - 1)}^{3} + 2^{3} = (x - 1 + 2) [{(x - 1)}^{2} + 4 - 2 (x - 1)] = (x + 1) [x^{2} + 1 - 2 x + 4 - 2 x + 2] = (x + 1) (x^{2} - 4 x + 7)$

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Similar questions

x^{3} + 3 x^{2} + 3 x - 7

x^{3} - 3 x^{2} + 3 x + 7

Factorise:
$x^{3} - 3 x^{2} + 3 x + 7$

x^{3} + 3 x^{2} + 3 x + 7 = 0

Factories

1. x³-3x²+3x+7

Factorise
$x^{3} - 512$

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