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Question

Factorise: x3-3x2+3x+7


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Solution

We need to factorise x3-3x2+3x+7:

x3-3x2+3x+7=x3+x2-4x2-4x+7x+7=x2(x+1)-4x(x+1)+7(x+1)=(x+1)(x2-4x+7)

Hence, the factors of x3-3x2+3x+7 are x+1 and x2-4x+7.


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