1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard IX
Mathematics
Factorisation of a Polynomial
factorise x3-...
Question
factorise x3-x2-14x+24 by using factor theorem
Open in App
Solution
Dear student
L
e
t
f
(
x
)
=
x
3
-
x
2
-
14
x
+
24
b
e
t
h
e
g
i
v
e
n
p
o
l
y
n
o
m
a
i
l
.
T
h
e
f
a
c
t
o
r
s
o
f
t
h
e
c
o
n
s
tan
t
t
e
r
m
24
i
n
t
h
i
s
p
o
l
y
n
o
m
a
i
l
a
r
e
±
1
,
±
2
,
±
3
,
±
4
,
±
6
,
±
8
,
±
12
a
n
d
±
24
.
W
e
h
a
v
e
,
f
(
2
)
=
2
3
-
2
2
-
14
2
+
24
=
0
⇒
x
-
2
i
s
a
f
a
c
t
o
r
o
f
f
(
x
)
.
s
i
m
i
l
a
r
l
y
,
i
t
c
a
n
b
e
v
e
r
i
f
i
e
d
t
h
a
t
(
x
-
3
)
a
n
d
(
x
+
4
)
a
r
e
f
a
c
t
o
r
s
o
f
f
(
x
)
.
S
i
n
c
e
f
(
x
)
i
s
a
p
o
l
y
n
o
m
a
i
l
o
f
d
e
g
r
e
e
3
.
S
o
i
t
c
a
n
n
o
t
h
a
v
e
m
o
r
e
t
h
a
n
3
l
i
n
e
a
r
f
a
c
t
o
r
s
.
H
e
n
c
e
,
f
(
x
)
=
k
(
x
-
2
)
(
x
-
3
)
(
x
+
4
)
,
w
h
e
r
e
k
i
s
a
c
o
n
tan
t
Regards
Suggest Corrections
0
Similar questions
Q.
Using factor theorem factorise
x
3
−
3
x
2
−
9
x
−
5
Q.
using the factor theorem factorise the following
x
3
−
6
x
2
+
11
x
−
6
Q.
Factorise
x
3
−
23
x
2
+
142
x
−
120
by using factor theorem.
Q.
Factorise
x
2
–
5
x
+
6
by using the Factor Theorem.
Q.
Factorise
x
3
−
10
x
2
−
53
x
−
42
, using factor theorem.
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Let's Solve a Problem
MATHEMATICS
Watch in App
Explore more
Factorisation of a Polynomial
Standard IX Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app