Factories y2−5y+6 by using splitting middle term.
Given: y2−5y+6
We have to find two numbers whose product is 6y2 and sum is −5y.
Using, middle term splitting, we get,
=y2−3y−2y+6
=y(y−3)−2(y−3)
=(y−2)(y−3)
Therefore, y2−5y+6=(y−2)(y−3)
Factorise x^2+8 by splitting middle term.
Factorise the following by splitting the middle term and find the roots.2x2+x–6=0