Factorise:
$y^{2} + 7 y - 144$

(y + 16) (y + 8)

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(y + 16) (y - 9)

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(y - 16) (y - 9)

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(y + 16) (y - 8)

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Solution

The correct option is C $(y + 16) (y - 9)$
$y^{2} + 7 y - 144$
$= y^{2} + 16 y - 9 y - 144$
$= y (y + 16) - 9 (y + 16)$
$= (y + 16) (y - 9)$

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Similar questions

8

x -

y -

9 x^{2} - 16 y^{2} = 144

x^{2} + y^{2} = 9

9 x^{2} - 16 y^{2} = 144

x^{2} + y^{2} = 9

9 x^{2} - 16 y^{2} = 144

x^{2} + y^{2} = 9

9 x^{2} - 16 y^{2} = 144

x^{2} + y^{2} = 9

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