Z^2+12z+27 =z^2+9z+3z+27 ∵ 27=9 × 3 amp; 12=9+3 amp; =z(z+9)+3(z+9) =(z+9)(z+3) ...

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Factorisation by Regrouping Terms

Factorise: z2...

Question

Factorise:
$z^{2} + 12 z + 27$

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Solution

$z^{2} + 12 z + 27 = z^{2} + 9 z + 3 z + 27 {\begin{matrix} ∵ 27 = 9 \times 3 12 = 9 + 3 \end{matrix}} = z (z + 9) + 3 (z + 9) = (z + 9) (z + 3)$

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