Factorise :
$z^{2} - 2 z - 8$

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Solution

To Factorise : $z^{2} - 2 z - 8$
By splitting the middle term
$= z^{2} - 4 z + 2 z - 8$
$= z (z - 4) + 2 (z - 4)$
$= (z + 2) (z - 4)$
So, $z^{2} - 2 z - 8 = (z + 2) (z - 4)$

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