Question

Factorise $z^2-\frac{9}{16}$ by using formula

• A. $(z+\frac{3}{9})(z-\frac{3}{4})$
• B. $(z+\frac{3}{4})(z-\frac{9}{4})$
• C. $(z+\frac{3}{4})(z-\frac{3}{4})$
• D. $(z-\frac{3}{4})(z-\frac{3}{4})$

Answer 1

Answer: (C)

$(z+\frac{3}{4})(z-\frac{3}{4})$

$Factorizing{z}^2-(3/4{)}^2,=(z-3/4\left)\right(z+3/4)$

using the identity $(a^2-b^2)=(a+b)(a-b)$