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Question

Factorise:
z−7+7xy−xyz

A
(zxy)(1xz)
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B
(z7)(1xy)
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C
z(7xzy)
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D
(z+7)(xy)
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Solution

The correct option is B (z7)(1xy)
z7+7xyxyz
=z7xyz+7xy
=1(z7)xy(z7)
=(z7)(1xy)
[Taking z7 common]

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