Factorised form of p2−17p−38 is a) (p−19)(p+2) b) (p−19)(p−2) c) (p+19)(p+2) d) (p+19)(p−2)
Open in App
Solution
a) (p−19)(p+2) →We have, p2−17p−38=p2−19p+2p−38 [by spliting the middle term, so that the product of their numerical coefficients is equal to the constant term] =p(p−19)+2(p−19)=(p−19)(p+2)[∵x2+(a+b)x+ab=(x+a)(x+b)]