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Factorisation Using Algebraic Identities

Factorising t...

Question

Factorising the polynomial $3 x^{2} - 6 x + 3$ , we get:

3 (x - 1) (x - 1)

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3 (x - 1) (x + 1)

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(x - 1) (x - 1)

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6 (x - 1) (x - 1)

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Solution

The correct option is A $3 (x - 1) (x - 1)$
$3 x^{2} - 6 x + 3$

$= 3 (x^{2} - 2 x + 1)$

$= 3 [{(x)}^{2} - 2 (x) (1) + (1)]$

$= 3 {(x - 1)}^{2}$ .... $[(∵ {(a - b)}^{2} = a^{2} - 2 a b + b^{2}]$

$= 3 (x - 1) (x - 1)$

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