Factorising $x^{2} + 6 x + 8$ , we get

(x + 1) (x + 8)

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(x + 6) (x + 2)

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(x + 10) (x - 2)

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(x + 4) (x + 2)

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Solution

The correct option is C $(x + 4) (x + 2)$
Given that: $x^{2} + 6 x + 8$
$= x^{2} + 4 x + 2 x + 8$ , (split middle term so that resultant is same)
$= (x^{2} + 4 x) + (2 x + 8)$ , (group pair of terms)
$= x (x + 4) + 2 (x + 4)$ , (factor each binomials)
$= (x + 4) (x + 2)$ , (factor out common factor $(x + 4)$ )

Hence option 'D' is correct choice

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