Factorize:

$0.64 m^{2} - 1.21 n^{2}$

$(0.8 n - 1.1 m) (0.8 n - 1.1 m)$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$(0.8 n + 1.1 m) (0.8 n - 1.1 m)$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$(0.8 m + 1.1 n) (0.8 m + 1.1 n)$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$(0.8 m + 1.1 n) (0.8 m - 1.1 n)$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
$(0.8 m + 1.1 n) (0.8 m - 1.1 n)$

$\Rightarrow 0.64 m^{2} - 1.21 n^{2}$

[Using identity $a^{2} - b^{2} = (a + b) (a - b)$ ]

$\Rightarrow (0.8 m)^{2} - (1.1 n)^{2}$

$\Rightarrow (0.8 m + 1.1 n) (0.8 m - 1.1 n)$

Suggest Corrections

Similar questions

Factorize:

$0.64 m^{2} - 1.21 n^{2}$

\sqrt{m^{2} n^{2}} \times \sqrt[6]{m^{2} n^{2}} \times \sqrt[3]{m^{2} n^{2}}

= m^{2} n^{2}

(\frac{m + \sqrt{m^{2} - n^{2}}}{m - \sqrt{m^{2} - n^{2}}} - \frac{m - \sqrt{m^{2} - n^{2}}}{m + \sqrt{m^{2} - n^{2}}}) \frac{n^{2}}{4 m \sqrt{m^{2} - n^{2}}}

\frac{m^{2} + n^{2}}{m^{2} - n^{2}}

Join BYJU'S Learning Program