Factorize-0-64 m 2-1-21 n 2A- 0-8 m -1-1 n 0-8 m -1-1 n B- 0-8 n -1-1 m 0-8 n -1-1 m C- 0-8 m -1-1 n 0-8 m -1-1 n D- 0-8 n -1-1 m 0-8 n -1-1 m

The correct option is C (0.8m + 1.1n) (0.8m 1.1n) ⇒ 0.64 m^2 1.21 n^2 [Using identity a^2 b^2 = (a+b)(a b)] ⇒ (0.8 m)^2 (1.1n)^2 ⇒ (0.8m + 1.1n) (0.8m ...

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Standard VIII

Mathematics

Factorisation Using Algebraic Identities

Factorize:0.6...

Question

Factorize:

$0.64 m^{2} - 1.21 n^{2}$

$(0.8 n + 1.1 m) (0.8 n - 1.1 m)$

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$(0.8 m + 1.1 n) (0.8 m + 1.1 n)$

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$(0.8 m + 1.1 n) (0.8 m - 1.1 n)$

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$(0.8 n - 1.1 m) (0.8 n - 1.1 m)$

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Solution

The correct option is C
$(0.8 m + 1.1 n) (0.8 m - 1.1 n)$

$\Rightarrow 0.64 m^{2} - 1.21 n^{2}$

[Using identity $a^{2} - b^{2} = (a + b) (a - b)$ ]

$\Rightarrow (0.8 m)^{2} - (1.1 n)^{2}$

$\Rightarrow (0.8 m + 1.1 n) (0.8 m - 1.1 n)$

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Factorize: 0.64 m2−1.21 n2

The correct option is C (0.8m+1.1n)(0.8m−1.1n) ⇒0.64 m2−1.21 n2 [Using identity a2−b2=(a+b)(a−b)] ⇒(0.8m)2−(1.1n)2 ⇒(0.8m+1.1n)(0.8m−1.1n)

Factorize:

$0.64 m^{2} - 1.21 n^{2}$

The correct option is C
$(0.8 m + 1.1 n) (0.8 m - 1.1 n)$

$\Rightarrow 0.64 m^{2} - 1.21 n^{2}$

[Using identity $a^{2} - b^{2} = (a + b) (a - b)$ ]

$\Rightarrow (0.8 m)^{2} - (1.1 n)^{2}$

$\Rightarrow (0.8 m + 1.1 n) (0.8 m - 1.1 n)$