Factorize:
$1 - 8 a^{3}$

(1 - 2 a) (1 - 2 a + 4 a^{2})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(1 - 2 a) (1 + 2 a + 4 a^{2})

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(1 + 2 a) (1 + 2 a + 4 a^{2})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(1 - a) (1 + 2 a + 4 a^{2})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $(1 - 2 a) (1 + 2 a + 4 a^{2})$
$1 - 8 a^{3}$
Using,
$a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2})$
$= (1)^{3} - (2 a)^{3}$
$= (1 - 2 a) [(1^{2}) + 1 \times 2 a + (2 a)^{2}]$
$= (1 - 2 a) (1 + 2 a + 4 a^{2})$

Suggest Corrections

Similar questions

2 a + \frac{1}{2 a} = 8

4 a^{2} + \frac{1}{4 a^{2}}

Factorise $2 a^{7} - 128 a$

8 a^{3} - b^{3} - 4 a x + 2 b x

(2 a + \frac{1}{2 a}) (2 a - \frac{1}{2 a})

4 a^{2} - \frac{1}{4 a^{2}}

Join BYJU'S Learning Program