CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Factorize: (1x2)(1y2)+4xy

Open in App
Solution

(1x2)(1y2)+4xy
expand
=1x2y2+x2y2+4xy
=1x2y2+x2y2+2xy+2xy
=1+x2y2+2xy(x2+y22xy)
=(1+(xy))2(yx)2[a2b2]
=(1+xy+yx)(1+xyy+x)a2b2=(a+b)(ab)

1172674_1246569_ans_699b5d59b9f344f89032adec5dd068f3.jpeg

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solving QE by Factorisation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon