Factorize :
$12 (3 x - 2 y)^{2} - 3 x + 2 y - 1$

(9 x - 6 y - 1) (12 x - 8 y - 1)

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(9 x - 6 y - 1) (12 x + 8 y + 1)

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(9 x + 6 y - 1) (12 x - 8 y + 1)

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(9 x - 6 y - 1) (12 x - 8 y + 1)

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Solution

The correct option is C $(9 x - 6 y - 1) (12 x - 8 y + 1)$
$12 (3 x - 2 y)^{2} - 3 x + 2 y - 1$
Let $(3 x - 2 y)$ be $a$
$= 12 a^{2} - a - 1$
$= 12 a^{2} - 4 a + 3 a - 1$
$= 4 a (3 a - 1) + 1 (3 a - 1)$
$= (3 a - 1) (4 a + 1)$
Putting the value of $a$
$[3 (3 x - 2 y) - 1] [4 (3 x - 2 y) + 1]$
$= (9 x - 6 y - 1) (12 x - 8 y + 4)$

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