Factorize:
$121 a^{2} + 154 a b + 49 b^{2}$

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Solution

Given expression is $121 a^{2} + 154 a b + 49 b^{2}$
Using $(x + y)^{2} = x^{2} + y^{2} + 2 x y$
We have $x = 11 a, y = 7 b$
Therefore, $121 a^{2} + 154 a b + 49 b^{2} = (11 a + 7 b)^{2}$
Thus factors are $(11 a + 7 b), (11 a + + 7 b)$ .

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