Factorize $125 a^{3} + 343 b^{3}$ .

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Solution

given, $125 a^{3} + 343 b^{3}$

$= (5 a)^{3} + (7 b)^{3}$

Using identity,
$a^{3} + b^{3} = (a + b) (a^{2} - a b + b^{2})$

$(5 a)^{3} + (7 b)^{3} = (5 x + 7 y) (25 x^{2} - 35 x + 49 y^{2})$

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Factorize $64 a^{3} - 343 b^{3}$

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Give the factorization of 64a³-343b³ ?

27 - 125 a^{3} - 135 a + 225 a^{2}

125 a^{3} + b^{3} + 64 c^{3} - 60 a b c

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